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    • Posted by Sayantika Mondal 1 week, 2 days ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
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    • Posted by Shobha V 1 week, 4 days ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
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    Posted by Naushad Jamil Ahmed Qureshi 1 week, 6 days ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Naushad Jamil Ahmed Qureshi 1 week, 6 days ago

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    • Posted by Sleeping Beauty Rasi 1 month, 1 week ago

    CBSE > Class 12 > Applied Mathematics
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    Posted by Pranav Makkar 3 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Yash Jain 3 months, 3 weeks ago

    P(3) = 0.18

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    • Posted by Abhay Verma 3 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
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    Posted by Sayak Mondal 5 months ago

    CBSE > Class 12 > Applied Mathematics
    • 5 answers

    Sayak Mondal 5 months ago

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    Sayak Mondal 5 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    Sayak Mondal 5 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    Sayak Mondal 5 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    Sayak Mondal 5 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    ANSWER

    • Posted by Kajal Verma 6 months, 1 week ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Shalin8 B 6 months, 2 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Shivam Khandelwal 7 months, 1 week ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Aman Kumar 7 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Shivansh Kanojia 8 months, 2 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Kalp Shrimal Jain 8 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Bhumi Goel 10 months ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Devansh Parihar 10 months, 1 week ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Nisarg Parmar 11 months, 2 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Royal Baniye 11 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Mahitesh Rawat 11 months, 2 weeks ago

    Continuity ?

    0Thank You

    ANSWER

    • Posted by Sanchita Shrivastava 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Sanchita Shrivastava 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Ayushi Singh 11 months, 1 week ago

    I want this

    3Thank You

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    • Posted by Vetali Mittal 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Indhumathi.J Jambu 1 year, 2 months ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Aikansh Gupta 1 year, 3 months ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Tanushri Bhayani 1 year, 3 months ago

    Kindly provide complete question !!

    0Thank You

    ANSWER

    • Posted by Rupa Josyula 1 year, 3 months ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Lakshya Sharma 1 year, 1 month ago

    Tatti

    0Thank You

    Pushkar Mahapale 1 year, 3 months ago

    apne iska premium subscription like raha hai kya

    1Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 3 months ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Preeti Dabral 1 year, 3 months ago

    The effective rate is the actual rate compounded annually. Therefore, the required sum S is given by
    S = 12000 (1 + {tex}\frac{3}{100}{/tex})10 (1 + {tex}\frac{4}{100}{/tex})4 (1 + {tex}\frac{5}{100}{/tex})2
    {tex}\Rightarrow{/tex} S = 12000 (1.03)10 (1.04)4 (1.05)2
    {tex}\Rightarrow{/tex} S = 12000 (1.34391638) (1.16985856) (1.1025) = 20800.10
    Hence, the amount is ₹20,800.10

    0Thank You

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    • Posted by Tanushri Bhayani 1 year, 3 months ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Preeti Dabral 1 year, 3 months ago

    ₹2480.57

    0Thank You

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    • Posted by Tanushri Bhayani 1 year, 3 months ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Preeti Dabral 1 year, 3 months ago

    7

    0Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 3 months ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Tanushri Bhayani 1 year, 3 months ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Tanushri Bhayani 1 year, 3 months ago

    Ohh' alright

    0Thank You

    Nishant Dogra 1 year, 3 months ago

    Using the properties of matrix algebra, we can expand the expression (I + A)3 as follows: (I + A)3 = (I + A)(I + A)(I + A) = (I + A)(I2 + 2IA + A2) = (I + A)(I + 2A + A) = I2 + 3IA + 3A2 + A3 = I + 3A + 3A2 + A3 (since A2 = A) Substituting this expression into the original equation, we get: (I + A)3 - 7A = (I + 3A + 3A2 + A3) - 7A = I + 2A + 3A2 - 7A = I - 5A + 3A2 Therefore, (I + A)3 - 7A is equal to I - 5A + 3A2.

    4Thank You

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    • Posted by Bhumika Jain 1 year, 4 months ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Tanushri Bhayani 1 year, 4 months ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Tanushri Bhayani 1 year, 3 months ago

    Hmm' got it 👍 thanks

    0Thank You

    Nishant Dogra 1 year, 3 months ago

    Solution We can calculate the product AB as follows: AB = [[-i, 0], [0, i]] [[1, 0], [0, -1]] = [[-i, 0], [0, -i]] Next, we can calculate the determinant of AB as follows: det(AB) = (-i) * (-i) - 0 * 0 (determinant of a 2x2 matrix) = 1 Now, we can use the formula for the product of determinants to find the determinant of A multiplied by the determinant of (i^2-1)B: det(A) * det((i^2-1)B) = det(AB) det(A) * (i^2-1)^2 * det(B) = 1 Substituting the known values, we get: det(A) * (i^2-1)^2 * (-1/1) = 1 det(A) * 4 = 1 det(A) = 1/4 Since A is a 2x2 matrix, its determinant can be calculated as follows: det(A) = (-i) * i - 0 * 0 (determinant of a 2x2 matrix) = -1 Therefore, we have a contradiction: det(A) = -1 and det(A) = 1/4. Hence, there is no value of a that satisfies the given conditions.

    1Thank You

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